Integrand size = 27, antiderivative size = 74 \[ \int \frac {\cos (c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^3} \, dx=-\frac {3 \log (1+\sin (c+d x))}{a^3 d}+\frac {\sin (c+d x)}{a^3 d}+\frac {1}{2 a d (a+a \sin (c+d x))^2}-\frac {3}{d \left (a^3+a^3 \sin (c+d x)\right )} \]
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Time = 0.06 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {2912, 12, 45} \[ \int \frac {\cos (c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^3} \, dx=\frac {\sin (c+d x)}{a^3 d}-\frac {3}{d \left (a^3 \sin (c+d x)+a^3\right )}-\frac {3 \log (\sin (c+d x)+1)}{a^3 d}+\frac {1}{2 a d (a \sin (c+d x)+a)^2} \]
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Rule 12
Rule 45
Rule 2912
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {x^3}{a^3 (a+x)^3} \, dx,x,a \sin (c+d x)\right )}{a d} \\ & = \frac {\text {Subst}\left (\int \frac {x^3}{(a+x)^3} \, dx,x,a \sin (c+d x)\right )}{a^4 d} \\ & = \frac {\text {Subst}\left (\int \left (1-\frac {a^3}{(a+x)^3}+\frac {3 a^2}{(a+x)^2}-\frac {3 a}{a+x}\right ) \, dx,x,a \sin (c+d x)\right )}{a^4 d} \\ & = -\frac {3 \log (1+\sin (c+d x))}{a^3 d}+\frac {\sin (c+d x)}{a^3 d}+\frac {1}{2 a d (a+a \sin (c+d x))^2}-\frac {3}{d \left (a^3+a^3 \sin (c+d x)\right )} \\ \end{align*}
Time = 0.17 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.95 \[ \int \frac {\cos (c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^3} \, dx=\frac {-12 \log (1+\sin (c+d x))+4 \sin (c+d x)+\frac {-9-10 \sin (c+d x)}{(1+\sin (c+d x))^2}+\frac {\sin ^2(c+d x)}{(1+\sin (c+d x))^2}}{4 a^3 d} \]
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Time = 0.34 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.68
method | result | size |
derivativedivides | \(\frac {\sin \left (d x +c \right )-\frac {3}{1+\sin \left (d x +c \right )}-3 \ln \left (1+\sin \left (d x +c \right )\right )+\frac {1}{2 \left (1+\sin \left (d x +c \right )\right )^{2}}}{d \,a^{3}}\) | \(50\) |
default | \(\frac {\sin \left (d x +c \right )-\frac {3}{1+\sin \left (d x +c \right )}-3 \ln \left (1+\sin \left (d x +c \right )\right )+\frac {1}{2 \left (1+\sin \left (d x +c \right )\right )^{2}}}{d \,a^{3}}\) | \(50\) |
parallelrisch | \(\frac {\left (6 \cos \left (2 d x +2 c \right )-24 \sin \left (d x +c \right )-18\right ) \ln \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (-12 \cos \left (2 d x +2 c \right )+48 \sin \left (d x +c \right )+36\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+9 \cos \left (2 d x +2 c \right )-15 \sin \left (d x +c \right )+\sin \left (3 d x +3 c \right )-9}{2 d \,a^{3} \left (-3+\cos \left (2 d x +2 c \right )-4 \sin \left (d x +c \right )\right )}\) | \(128\) |
risch | \(\frac {3 i x}{a^{3}}-\frac {i {\mathrm e}^{i \left (d x +c \right )}}{2 d \,a^{3}}+\frac {i {\mathrm e}^{-i \left (d x +c \right )}}{2 d \,a^{3}}+\frac {6 i c}{d \,a^{3}}-\frac {2 i \left (-3 \,{\mathrm e}^{i \left (d x +c \right )}+5 i {\mathrm e}^{2 i \left (d x +c \right )}+3 \,{\mathrm e}^{3 i \left (d x +c \right )}\right )}{d \,a^{3} \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )^{4}}-\frac {6 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )}{d \,a^{3}}\) | \(134\) |
norman | \(\frac {\frac {6 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d a}+\frac {6 \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}+\frac {110 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}+\frac {110 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}+\frac {156 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}+\frac {156 \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}+\frac {24 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}+\frac {24 \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}+\frac {192 \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}+\frac {192 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}+\frac {56 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}+\frac {56 \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{4} a^{2} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{5}}-\frac {6 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{d \,a^{3}}+\frac {3 \ln \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d \,a^{3}}\) | \(303\) |
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Time = 0.28 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.28 \[ \int \frac {\cos (c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^3} \, dx=\frac {4 \, \cos \left (d x + c\right )^{2} - 6 \, {\left (\cos \left (d x + c\right )^{2} - 2 \, \sin \left (d x + c\right ) - 2\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) + 2 \, {\left (\cos \left (d x + c\right )^{2} + 1\right )} \sin \left (d x + c\right ) + 1}{2 \, {\left (a^{3} d \cos \left (d x + c\right )^{2} - 2 \, a^{3} d \sin \left (d x + c\right ) - 2 \, a^{3} d\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 303 vs. \(2 (63) = 126\).
Time = 0.72 (sec) , antiderivative size = 303, normalized size of antiderivative = 4.09 \[ \int \frac {\cos (c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^3} \, dx=\begin {cases} - \frac {6 \log {\left (\sin {\left (c + d x \right )} + 1 \right )} \sin ^{2}{\left (c + d x \right )}}{2 a^{3} d \sin ^{2}{\left (c + d x \right )} + 4 a^{3} d \sin {\left (c + d x \right )} + 2 a^{3} d} - \frac {12 \log {\left (\sin {\left (c + d x \right )} + 1 \right )} \sin {\left (c + d x \right )}}{2 a^{3} d \sin ^{2}{\left (c + d x \right )} + 4 a^{3} d \sin {\left (c + d x \right )} + 2 a^{3} d} - \frac {6 \log {\left (\sin {\left (c + d x \right )} + 1 \right )}}{2 a^{3} d \sin ^{2}{\left (c + d x \right )} + 4 a^{3} d \sin {\left (c + d x \right )} + 2 a^{3} d} + \frac {2 \sin ^{3}{\left (c + d x \right )}}{2 a^{3} d \sin ^{2}{\left (c + d x \right )} + 4 a^{3} d \sin {\left (c + d x \right )} + 2 a^{3} d} - \frac {12 \sin {\left (c + d x \right )}}{2 a^{3} d \sin ^{2}{\left (c + d x \right )} + 4 a^{3} d \sin {\left (c + d x \right )} + 2 a^{3} d} - \frac {9}{2 a^{3} d \sin ^{2}{\left (c + d x \right )} + 4 a^{3} d \sin {\left (c + d x \right )} + 2 a^{3} d} & \text {for}\: d \neq 0 \\\frac {x \sin ^{3}{\left (c \right )} \cos {\left (c \right )}}{\left (a \sin {\left (c \right )} + a\right )^{3}} & \text {otherwise} \end {cases} \]
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Time = 0.19 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.96 \[ \int \frac {\cos (c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^3} \, dx=-\frac {\frac {6 \, \sin \left (d x + c\right ) + 5}{a^{3} \sin \left (d x + c\right )^{2} + 2 \, a^{3} \sin \left (d x + c\right ) + a^{3}} + \frac {6 \, \log \left (\sin \left (d x + c\right ) + 1\right )}{a^{3}} - \frac {2 \, \sin \left (d x + c\right )}{a^{3}}}{2 \, d} \]
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Time = 0.34 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.76 \[ \int \frac {\cos (c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^3} \, dx=-\frac {\frac {6 \, \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right )}{a^{3}} - \frac {2 \, \sin \left (d x + c\right )}{a^{3}} + \frac {6 \, \sin \left (d x + c\right ) + 5}{a^{3} {\left (\sin \left (d x + c\right ) + 1\right )}^{2}}}{2 \, d} \]
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Time = 0.08 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.80 \[ \int \frac {\cos (c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^3} \, dx=\frac {\sin \left (c+d\,x\right )}{a^3\,d}-\frac {3\,\ln \left (\sin \left (c+d\,x\right )+1\right )}{a^3\,d}-\frac {3\,\sin \left (c+d\,x\right )+\frac {5}{2}}{a^3\,d\,{\left (\sin \left (c+d\,x\right )+1\right )}^2} \]
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